What is the Momentum of an Explosion?
The forces
involved in an explosion make objects
move away from each
other very quickly.
This is an example of Newton's
third law of motion.
The law of conservation
of momentum tells us that the
total momentum
is the same, before
and
after the explosion.
Before
an explosion the objects are not
moving
and so the total momentum
is zero.
After the explosion
the total momentum is also still zero.
The momentum of objects
moving in one direction
must be exactly balanced by the
momentum of objects
moving in the opposite
direction.
An example of an explosion
is a gun firing a bullet.
The same force that pushes
the bullet forwards
and gives it a fast velocity
also pushes the gun backwards
(called recoil velocity).
Q1. A gun
has a mass of 2·5
kg and a recoil velocity of
8 m/s.
What is the velocity of the bullet
if it has a mass of 0·02 kg?
A1. The momentum of
the gun going backwards
after the explosion, must be the
same as the momentum
of the bullet going forwards.
momentum = mass x velocity
For the gun
momentum = 2·5
x 8
= 20·0 kgm/s.
For the bullet
20·0 =
0·02
x v
v
= 20·0
÷ 0·02
= 1000 m/s.
The velocity of the bullet = 1000 m/s.
Links
Forces and
Motion Revision Questions
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