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What is the Current in each Branch of a Parallel Circuit?

From the
previous page,
the
current A_{2}
flowing

through the branch with the 2
ohm resistor is 6 amps.

The
current A_{3}
flowing through the
3 ohm resistor is

I = V ÷ R

= 12 ÷ 3

= 4 amps.

The
current A_{4}
flowing through the
4 ohm resistor is

I = V ÷ R

= 12 ÷ 4

= 3 amps.

Notice that the bigger the resistance, the smaller the current.

What is the Total Current in a Parallel Circuit?

The total
current at A_{1} or A_{5} is

found
by
adding up the current in each
branch.

A_{1} = A_{2} +
A_{3} + A_{4}

= 6 + 4 + 3

= 13 amps.

This is much
larger than the current of
1·333
amps

that flows through a series circuit with

the same resistors and
the same supply
voltage.

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